Re: [FISIKA] Soal trigonometri

[bozhart]

Terima kasih Eka Subyantara,

Rumus itu kok nggak ada variabel X ? :p
Mungkin maksudnya ini ya?

Y = X * tg(A) * tg(B) / [ tg(A) - tg(B) ]

Rumus itu juga dipost oleh Petrus Indrianto.

Btw, tadi saya baru post tentang ada rumus yg lebih sederhana dgn
menggunakan fungsi cotangen.

Thanks



--- In fisika_indonesia@yahoogroups.com, "Eka Subyantara"
<[EMAIL PROTECTED]> wrote:
>
> A=sudut alpha
> B=sudut beta
> y = [ tg(A) - tg(B) ] / [ tg(A) * tg(B) ]



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