Re: [Haskell] Recursive definition of fibonacci with Data.Vector

[Edgar Z. Alvarenga]

On Sun, 07/Mar/2010 at 17:04 -0500, Brian Sniffen wrote:
> To what do you expect 'v' to refer?

Data.Vector
 
> Why use 'let' for the definition?
> 
> And then once you sort it out to something like:
> 
>     fib = 0 `V.cons` (1 `V.cons` V.zipWith (+) fib (V.tail fib))

Was just a typo (the line above was copy from ghci).
 
> The three Vector operations used here are strict in the length of
> their arguments. So what length should 'fib' have?  2 more than its
> own length... which is more RAM than this computer has.

Ok, now I understood, is because of the strictness. The next time I 
would look in the source code first.

Thanks,
Edgar
 
> -Brian
> 
> On Sun, Mar 7, 2010 at 3:49 PM, Edgar Z. Alvarenga <ed...@ymonad.com> wrote:
> > Hello,
> >
> > why I can't define a recursive vector using Data.Vector, like in
> > the example:
> >
> > import qualified Data.Vector as V
> >
> > let fib = 0 `V.cons` (1 `V.cons` V.zipWith (+) fib (V.tail v))
> >
> > Cheers,
> > Edgar
> > _______________________________________________
> > Haskell mailing list
> > Haskell@haskell.org
> > http://www.haskell.org/mailman/listinfo/haskell
> >
> 
> 
> 
> -- 
> Brian Sniffen
> http://evenmere.org/~bts/
> <b...@evenmere.org>
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