Re: [linux-programming] regex

[Hari Hendaryanto]

Yohanes Nugroho wrote:

Halo,

2009/12/1 Hari Hendaryanto <har...@csmcom.com>:

#!/bin/bash
if [ -z "`echo $1 | awk '/^[[:space:]]+/{print}'`" ]; then

tambahkan kutip di antara $1, jadi

if [ -z "`echo "$1" | awk '/^[[:space:]]+/{print}'`" ]; then

it work!!! :) thanks

lalu saya install gawk dan jadi jalan. Mungkin pakai egrep (pake "e"
bukan grep biasa, atau pake grep -E) lebih portabel:

#!/bin/sh
echo "$1" | egrep -q ^[[:space:]]
if [ $? == 0 ]; then
        echo "NOT OK";
else
        echo "OK";
fi

it work  juga :)

kesimpulan cuma kekurangan doublequote aja di parameter $1

thanks


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