At 04:39 PM 12/11/03 +0100, [EMAIL PROTECTED] wrote:
>    When Mp is prime, then 
>
>        a[p-2]^2 == 2 == 2*Mp + 2 = 2^(p+1)  (mod Mp).
>
>Taking square roots, either
>
>       a[p-2] ==  2^((p+1)/2) mod Mp
>or
>       a[p-2] == -2^((p+1)/2) mod Mp.
>
>Around 20 years ago I heard that nobody could predict
>which of these would occur.

After M29 was discovered, that was the very first question Dick Lehmer asked.
I think it interested him more than the value of p!! 

--Luke


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