Hi Rik and autumnus,
Sorry for my late reply, but thank you very much for your suggestions on
this topic.
Your calculations are very complicated I think.
However, the type area is not the end of the story.
Unfortunately, the line length remains the same with your suggestions,
even if the font size is reduced. For good readability, however, the
number of characters in the line should remain more or less constant and
not increase.
In any case, that's what I've read.
I have therefore orientated myself on this:
https://wiki.contextgarden.net/Introduction/From_LaTeX_to_ConTeXt/KOMA-scrartcl_Type_Area
It looks like this for me now:
\definebodyfontenvironment[12pt][interlinespace=15pt]
\setupbodyfont[libertinus, 12pt]
\setuppagenumbering[location={footer,middle}, alternative=doublesided]
\setupindenting[yes, small, next]
%\enablemode[BCOR]
% Set binding correction value .
\doifmodeelse{BCOR}{\def\bindingcorr{5mm}}{\def\bindingcorr{0pt}}
% Set visible page width.
\newdimen\PageWidth \PageWidth=\dimexpr(\paperwidth-\bindingcorr)
% Determine the paper aspect ratio.
\edef\Ratio{0.618} %Golden Ratio
% Set the textarea height proportional to the width.
\newdimen\Height \Height=41\baselineskip % constant number of
lines (41)
\newdimen\Width \Width=\dimexpr(\Ratio\Height)
% Set the margin/gutter widths to be equal on a full spread.
%\newdimen\Back \Back=\dimexpr(((\PageWidth - \Width) / 2) + \bindingcorr)
\enablemode[oneside]
\newdimen\Back
\doifmodeelse{oneside}
{\Back=\dimexpr(((\PageWidth - \Width) / 2) + \bindingcorr)}
{\Back=\dimexpr(((\PageWidth - \Width) / 3) + \bindingcorr)}
% Set the top and bottom margins in a 1:2 ratio, ignoring headers.
\edef\Top{\the\dimexpr((\paperheight - \Height) / 3 - 3\lineheight)}
% Redefine \Height to include header and footer space.
\Height=\dimexpr(\Height + 8\lineheight)
% Set up the page layout using the calculated parameters.
\setuplayout[
backspace=\the\Back,
height=\the\Height,
width=\the\Width,
header=2.5\lineheight,
headerdistance=0.5\lineheight,
footer=4.5\lineheight,
footerdistance=0.5\lineheight,
bottom=2\lineheight,
bottomdistance=0.5\lineheight,
margindistance=0.2\lineheight,
topspace=\Top,
grid=on,
]
\starttext
\showgrid
\input knuth
\input tufte
\input knuth
\input tufte
\showlayout[1, pt, mm]
\stoptext
If I am wrong, please correct me.
Greetings
Thomas
Am 24.02.25 um 19:33 schrieb Rik Kabel:
On 2025-02-24 04:19, Thomas Meyer wrote:
Hello Hraban,
thanks for your tip.
Hopefully I'll find time to have a look at it after that busy weekend.
Regards
Thomas
Am 22.02.25 um 19:11 schrieb Henning Hraban Ramm:
Am 22.02.25 um 18:36 schrieb Thomas Meyer:
Thank you Wolfgang,
I guess I'm thinking too complicated. Ultimately, this should
result in a type area according to the golden ratio.
(textheight = 660 pt = 1.618 * textwidth or something similar,
depending on the font size or interlinespace)
To simplify your code, you can replace many of these measures with
units, e.g. th, tw; see also lowlevel-registers.pdf
Perhaps this can help. It works for me. It lays out his page 155 (1st
edition paperback) bottom page, which has a 1.7 ratio type area on a
1.5 ratio page.
\doifmodeelse{frame}{\def\Paper{letter}}{\def\Paper{octavo}}
\definepapersize [octavo]
[width=6in,% 152.4mm, 433.62pt, 432bp
height=9in]% 228.6mm, 650..43pt, 648bp
\setuppapersize[octavo][\Paper]
\setuplayout [
%Bringhurst example on p155
%
% P = 1.5 (h=9", w=6") (648bp × 432bp) (54pc × 36pc)
% T = 1.7 (d=6.8", m=4") (491.44pt × 289.08pt) (489.6bp × 288bp)
(40.8pc × 24pc)
% (exclusive of running heads and folios)
% s = t = w/9 = 0.667" backspace and top margin
% e = 2s = 1.333" foredge
% ( f = h - t - d = 9" - 0.667" - 6.8" = 1.533"
% but must allow for footer/footerdistance in that )
% 36 lines @ 13.5pt = 486pt, 36 lines @ 13.45bp = 484.2bp
%
% Bringhurst calculations for 24pica width char/line
% libertinus alphabet width 10pt: 122pt 66
% libertinus alphabet width 10.5pt: 128pt 63
% libertinus alphabet width 11pt: 134pt 61
% libertinus alphabet width 12pt: 146pt 56
% backspace =
leftedge+leftedgedistance+leftmarginwidth+leftmargindistance
% cutspace = right...
% s = w/9 = leftmarginwidth+leftmargindistance = 0.667" = 48bp
% t = s = topspace + header+headerdistance
% header+headerdistance = 27bp
% topspace = 48bp - 27bp = 21bp
% e = 2×s = rightmarginwidth+rightmargindistance = 1.333" = 96bp
vz=2,
location=middle,
backspace=pw / 9,
cutspace=\backspace * 2,
width=\backspace * 6,
height=(\backspace * 6 * 1.7) + (4 * \lineheight),
topspace=\backspace - 2 * \lineheight,
headerdistance=\lineheight, header=\lineheight,
footerdistance=\lineheight, footer=\lineheight,
leftmargindistance=8bp, rightmargindistance=8bp,
leftmargin=\backspace - \leftmargindistance,
rightmargin=\cutspace - \rightmargindistance,
]
--
Rik
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If your question is of interest to others as well, please add an entry to the
Wiki!
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