The fact that the function name ends in % doesn't seem to make it an integer
function (although the QL user guide says that "the type of data returned by
the function is indicated by the type appended to the function identifier")
any more than parameter names have no type until they are set, so parameter
x% could be float or integer, depending on what it is made when parameters
are passed.
As a workaround, add INT in line 160
160 IF INT(x%) < i : RETurn INT(x%) : ELSE return INT(i)
Dilwyn
-----Original Message-----
From: Michael Bulford via Ql-Users
Sent: Thursday, August 10, 2017 5:54 PM
To: ql-users@lists.q-v-d.com ; ql-users-requ...@lists.q-v-d.com
Subject: [Ql-Users] Function type error
Hi all,
I've no idea whether this has been mentioned before, but consider this … 100
:110 PRINT #0, Min_Int%(330.7, 440.7)120 PAUSE -1130 STOP140 :150 DEFine
FuNction Min_Int%(x%,i)160 IF x% < i : RETurn x% : ELSE : RETurn i170 END
DEFine The correct result should be 331, sincethis is an integer function.On
QPC2, SBASIC gives the result as 330.7QLiberator likewise also gives 330.7
Can anything be done? Michael
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