Try this: library(zoo) plot(na.approx(zoo(as.matrix(data[-1]), data[,1])), plot.type = "single")
See ?na.approx, ?plot.zoo, ?xyplot.zoo and vignette("zoo") On 9/7/07, Markus Schmidberger <[EMAIL PROTECTED]> wrote: > Hello, > > I have this kind of dataframe and have to plot it. > > data <- data.frame(sw= c(1,2,3,4,5,6,7,8,9,10,11,12,15), > zehn = > c(33.44,20.67,18.20,18.19,17.89,19.65,20.05,19.87,20.55,22.53,NA,NA,NA), > zwanzig = > c(61.42,NA,26.60,23.28,NA,24.90,24.47,24.53,26.41,28.26,NA,29.80,35.49), > fuenfzig = > c(162.51,66.08,49.55,43.40,NA,37.77,35.53,36.46,37.25,37.66,NA,42.29,47.80) > ) > > The plot should have lines: > lines(fuenfzig~sw, data=data) > lines(zwanzig~sw, data=data) > > But now I have holes in my lines for the missing values (NA). How to > plot the lines without the holes? > The missing values should be interpolated or the left and right point > directly connected. The function approx interpolates the whole dataset. > Thats not my goal! > Is there no plotting function to do this directly? > > Best > Markus > > -- > Dipl.-Tech. Math. Markus Schmidberger > > Ludwig-Maximilians-Universität München > IBE - Institut für medizinische Informationsverarbeitung, > Biometrie und Epidemiologie > Marchioninistr. 15, D-81377 Muenchen > URL: http://ibe.web.med.uni-muenchen.de > Mail: Markus.Schmidberger [at] ibe.med.uni-muenchen.de > > ______________________________________________ > R-help@stat.math.ethz.ch mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > ______________________________________________ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.