Oleg Broytmann a écrit :
> On Thu, Mar 22, 2007 at 05:22:33PM +0100, Luper Rouch wrote:
>
>> I tried to use a custom style class, but it does not seem to be
>> involved in the ForeignKey name construction.
>>
>
> Please show a test program that triggers the problem with a style.
>
> Oleg.
>
Ok I found the answer to my question while trying to explain my problem :-)
To customize ForeignKey naming you have to reimplement
instanceAttrToIDAttr and instanceIDAttrToAttr in your style class.
Here is an example :
from sqlobject import *
class MyStyle(MixedCaseUnderscoreStyle):
def instanceAttrToIDAttr(self, attr):
return attr
def instanceIDAttrToAttr(self, attr):
return attr
class Foo(SQLObject):
pass
class Bar(SQLObject):
class sqlmeta:
style = MyStyle()
fooId = ForeignKey("Foo")
if __name__ == "__main__":
sqlhub.processConnection = connectionForURI("postgres://localhost/test")
Foo.createTable()
Bar.createTable()
This way Bar.fooId corresponds to bar.foo_id in the database ...
Thanks !
Luper Rouch
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