Riccardo and Ryan Thank you for your ideas.It seems that crossjoin is a new dataset api after spark2.x. my spark version is 1.6.3. Is there a relative api to do crossjoin? thank you.
-------------------------------- Thanks&Best regards! San.Luo ----- 原始邮件 ----- 发件人:Riccardo Ferrari <ferra...@gmail.com> 收件人:Ryan <ryan.hd....@gmail.com> 抄送人:luohui20...@sina.com, user <user@spark.apache.org> 主题:Re: Is there an operation to create multi record for every element in a RDD? 日期:2017年08月09日 16点54分 Depends on your Spark version, have you considered the Dataset api? You can do something like: val df1 = rdd1.toDF("userid") val listRDD = sc.parallelize(listForRule77) val listDF = listRDD.toDF("data") df1.crossJoin(listDF).orderBy("userid").show(60, truncate=false)+------+----------------------+|userid|data |+------+----------------------+|1 |1,1,100.00|1483891200,||1 |1,1,100.00|1483804800,|...|1 |1,1,100.00|1488902400,| |1 |1,1,100.00|1489075200,||1 |1,1,100.00|1488470400,|... On Wed, Aug 9, 2017 at 10:44 AM, Ryan <ryan.hd....@gmail.com> wrote: It's just sort of inner join operation... If the second dataset isn't very large it's ok(btw, you can use flatMap directly instead of map followed by flatmap/flattern), otherwise you can register the second one as a rdd/dataset, and join them on user id. On Wed, Aug 9, 2017 at 4:29 PM, <luohui20...@sina.com> wrote: hello guys: I have a simple rdd like :val userIDs = 1 to 10000val rdd1 = sc.parallelize(userIDs , 16) //this rdd has 10000 user id And I have a List[String] like below:scala> listForRule77 res76: List[String] = List(1,1,100.00|1483286400, 1,1,100.00|1483372800, 1,1,100.00|1483459200, 1,1,100.00|1483545600, 1,1,100.00|1483632000, 1,1,100.00|1483718400, 1,1,100.00|1483804800, 1,1,100.00|1483891200, 1,1,100.00|1483977600, 3,1,200.00|1485878400, 1,1,100.00|1485964800, 1,1,100.00|1486051200, 1,1,100.00|1488384000, 1,1,100.00|1488470400, 1,1,100.00|1488556800, 1,1,100.00|1488643200, 1,1,100.00|1488729600, 1,1,100.00|1488816000, 1,1,100.00|1488902400, 1,1,100.00|1488988800, 1,1,100.00|1489075200, 1,1,100.00|1489161600, 1,1,100.00|1489248000, 1,1,100.00|1489334400, 1,1,100.00|1489420800, 1,1,100.00|1489507200, 1,1,100.00|1489593600, 1,1,100.00|1489680000, 1,1,100.00|1489766400) scala> listForRule77.length res77: Int = 29 I need to create a rdd containing 290000 records. for every userid in rdd1 , I need to create 29 records according to listForRule77, each record start with the userid, for example 1(the userid),1,1,100.00|1483286400. My idea is like below:1.write a udfto add the userid to the beginning of every string element of listForRule77.2.use val rdd2 = rdd1.map{x=> List_udf(x))}.flatmap(), the result rdd2 maybe what I need. My question: Are there any problems in my idea? Is there a better way to do this ? -------------------------------- Thanks&Best regards! San.Luo