R C Macaulay
Tue, 15 Jul 2008 19:09:15 -0700
Richard----- Original Message ----- From: "Michel Jullian" <[EMAIL PROTECTED]>
To: <vortex-l@eskimo.com> Sent: Tuesday, July 15, 2008 8:13 PM Subject: [Vo]:Re: 70% solar panelsNope, 1000 W per m^2 at normal incidence is all there is to it. Per square centimeter that's 1000/(100*100) = 0.1 W, so as the wiki you quote says (quite clearly I would have thought) you need 2300 times that, which you can obtain e.g. by focussing sunlight with a concentration factor of 2300:1, to get 230W on a square centimeter...
Michel----- Original Message ----- From: "Brian Prothro" <[EMAIL PROTECTED]>
To: <vortex-l@eskimo.com> Sent: Wednesday, July 16, 2008 2:02 AM Subject: RE: [Vo]:Re: 70% solar panels
Now in my meager understandings in this area, I thought the 1000watts per square meter is defined as a narrow "1 nm bandwith" of sunlight and is "ameasuring standard" not the full power falling on the surface of the Earth.(The bands defined from below 400nm to 1700nm.) The test measurement is partially described as;"The ASTM G173 spectra represent terrestrial solar spectral irradiance on asurface of specified orientation under one and only one set of specifedatmospheric conditions. These distributions of power (watts per square meterper nanometer of bandwidth) as a function of wavelength provide a single common reference for evaluating spectrally selective PV materials withrespect to performance measured under varying natural and artifical sourcesof light with various spectral distributions..." "So, if a panel absorbs multiple bands and is more efficient, as DBK seem tohave resolved thru engineering, then there is more power. I also saw mentioned they work well in low light? (might be poor rcall on my part.) Now I am not an expert here, but the wiki says the power per square centimeter is 230 watts: "One sun" is a measurement equal to the solar power incident at noon on a clear summer day. I.e. in a 2300 sun system, approximately 230 watts per square centimeter are concentrated onto the cell system.[14] Does the Additional multiple junction solar technology not tend to be far higher in production that the normal 15%? DBK claims Five levels. I will ask DBK this directly... FYI -here is a chart of all current peak outputs for various technologies for solar cells http://en.wikipedia.org/wiki/Image:PVeff%28rev110707%29d.jpg Brian Prothro -----Original Message----- From: Michel Jullian [EMAIL PROTECTED] Sent: Tuesday, July 15, 2008 5:41 PM To: vortex-l@eskimo.com Subject: [Vo]:Re: 70% solar panels 1/ Making use of 70% of wavelengths doesn't mean 70% efficient! 2/ From the details you provide it seems that the panel has an embarkedbattery, which is fed by the ~200 W solar cells, and which is feeding a 3kWinverter. This allows them to claim 3kW for the panel, which indeed it can provide, but of course not more than 200/3000 = 7% of the full insolation time as they conveniently forget to specify. They probably hope some people will be gullible enough to believe it can provide 3kW full time, while receiving only 1.3kW solar irradiation! I see no reason why the product can't be a good one BTW, apart from the misleading way in which they present it. Michel
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