Thanks for the information. But AA, a pump by itself does not regulate the
level of the water. There must be some form of active level feedback applied
in order for this to occur. If no level sensing and feedback is used then
either the water totally fills up the device or it gets boiled off when subject
to a constant input flow.
The question can be clarified by finding a direct reference to level sensing in
Rossi's documentation in which case the pumps would need to be controlled by
software that cycles each of them on and off, or possibly adjusts the flow
dynamically. Can you point to such a document. A picture of a pump is not
adequate proof unless it is specified to have a limited maximum pressure that
would prevent the boiling point of the water from reaching significantly above
102 C if the ECAT device fills up.
I am sitting on the fence with respect to assuming that the test results are
measured accurately. Jed and others have presented a fairly convincing
arguement that all is not well. You and others appear to be 100% convinced
that Rossi is correct.
If Jed and allies are right then science must be able to explain what is
erroneous regarding the calibrated meter measurements. I am seeking that
explanation to fill in the blanks in the event that they are found correct. To
me that is the scientific method.
Let us put my latest hypothesis to rest which will enhance the proof that Rossi
is on the proper track. Is there any evidence of water level control feedback
that we can locate? I will look carefully at Engineer48 photos on Ecatworld
per your suggestion.
Dave
-----Original Message-----
From: a.ashfield <a.ashfi...@verizon.net>
To: vortex-l <vortex-l@eskimo.com>
Sent: Sat, Aug 20, 2016 8:10 pm
Subject: Re: [Vo]:Interesting Steam Calculation
If you look at the my original reference showing a link to photos of
Engineer48 on Ecatworld, it shows the many precision pumps for each Tiger
that maintain the correct water level in the reactors.
AA
On 8/20/2016 3:40 PM, David Roberson wrote:
Could you show me a reference to level gauges in each of the devices?
I do not recall seeing one so far.
Dave
-----Original Message-----
From: a.ashfield <a.ashfi...@verizon.net>
To: vortex-l <vortex-l@eskimo.com>
Sent: Sat, Aug 20, 2016 3:00 pm
Subject: Re: [Vo]:Interesting Steam Calculation
That would mean the Tiger E-Cats would have to be completely
flooded. But the level gauges don't show that.
Why not suggest pixie dust?
On 8/20/2016 1:51 PM, David Roberson wrote:
Today I made an interesting calculation that some may find
relevant to the ongoing discussions.
According to steam tables, the following could be
possible, assuming that I did not make a mistake in
my calculations.
Assume you have 1kg of water inside a solid
container at 130 C and 39.2 psi absolute. Then you place
a restriction device that allows all of the liquid to
eventually escape. Some of the liquid will immediatly flash
into vapor while most of the 1 kg remains in the liquid form
as it exits the restriction. If you assume that the
resulting mixture ends up at 102 C and 15.75 psi absolute
then it is possible to calculate the amount of vapor and
liquid that is present at that location.
The internal energy of the initial liquid at 130 C
is 546.388 kj/kg which in this case yields 546.388
thousand joules. I am assuming that this same amount of
energy remains within the liquid and vapor combintation of
the lower temperature and pressure stream.
When I solved the equation relating the quality of
the mixture to the various heat contents I
determined that there would be .053 kg or vapor and .947 kg
of liquid water at the output. On first glance, this result
suggests that it should be easy to separate the water from
the steam, but actually calculating the two volumes makes
that not so evident.
The volume of the vapor would be .053 kg * 1.565
cubic meters per kg = .0826 cubic meters. The
volume of the liquid water would be .947 kg* .001045 cubic
meters per kg = .000989 cubic meters.
Using the above numbers it appears that you would
have 83.488 times as much vapor by volume as
liquid. This is quite a large ratio which suggests that it
might well be possible to mistake a stream of mass with this
consistency as consisting of only vapor. Especially if a
visual technique were used.
I am not saying that this calculation reveals the
source of the Rossi test confusion, but that perhaps
it might open discussions that have not been considered so
far. I do recall that on earlier demonstrations that the
temperature within the ECATs was reported to be in the range
of 130 C.
Perhaps some of our mathematically inclined vortex
residents can take a few moments to verify that my
assumptions and calculations make sense.
Dave
