In reply to Jones Beene's message of Sun, 19 Feb 2017 12:36:18 -0800: Hi Jones,
Actually, I was wrong. It is energetically possible with light Hydrogen, and in fact yields just over 6 MeV. The reason it didn't show up in my program as a possible reaction is because my program doesn't take account of weak force reactions. However I still think that adding a proton to 62Ni is going to create 63Cu rather than 63Ni because weak force conversions are much slower than strong force mediated reactions. IOW the only way to get 63Ni is to create the neutron first, which implies getting 782 keV from somewhere, and this is not generally just found lying around. It would be possible if it could be taken from the energy of the reaction, but for that to happen, I think it would need to happen in the nucleus as part of the reaction process. This is unlikely because 63Ni decays to 63Cu, so the reaction would seem to require an inverse beta decay, just to make a later beta decay possible, which doesn't make sense. The direct reaction to 63Cu makes much more sense. ...but, if you can come up with a way of creating the neutron first, outside the nucleus, then more power to you. ;) >Robin, > >Agree it is not possible with hydrogen, but dense hydrogen is a >different story. > >Dense hydrogen includes the "virtual neutron" conceptions ... > >One reference is Daddi, Lino, "Virtual Neutrons In Orbital Capture And >In Neutron Synthesis" > >Another is Daddi, Lino, "Hydrogen Miniatoms" Both show up in Widom/Larsen > > >On 2/19/2017 11:47 AM, mix...@bigpond.com wrote: >> In reply to Jones Beene's message of Sun, 19 Feb 2017 08:29:23 -0800: >> Hi, >> [snip] >>> Would the >>> route for gain then first involve using dense hydrogen to convert Ni-62 >>> to Ni-63 using dense hydrogen in situ? >> This reaction is not energetically possible. The only possible light hydrogen >> reactions are:- >> >> 62Ni+1H => 63Cu + 6.122 MeV >> 62Ni+1H => 59Co + 4He + 0.346 MeV >> >> However it is possible with D:- >> >> 2H+62Ni => 63Cu + n + 3.898 MeV >> 2H+62Ni => 64Cu + 11.814 MeV >> 2H+62Ni => 63Ni + 1H + 4.613 MeV >> 2H+62Ni => 60Co + 4He + 5.614 MeV >> >> ..so the small amount of D naturally present in H could form some Ni63. >> >> Furthermore, the energy release from the intial fusion reaction would dwarf >> that >> from the decay of Ni63 anyway. >> >> Regards, >> >> Robin van Spaandonk >> >> http://rvanspaa.freehostia.com/project.html >> >> Regards, Robin van Spaandonk http://rvanspaa.freehostia.com/project.html
