Hello again,
A bit more testing indicates this error only occurs when the starting
element is more than 1, at least in my example.
The result should be 2 (elements 2 & 3) and it is 2 if I start with 1 but
the result is 4 if I start with 2!
And it seems only to occur when the result is greater than 1.
Thanks,
Alan

On Fri, Aug 19, 2016 at 6:07 PM, Alan Tilson <[email protected]> wrote:

> Hello everyone,
>
> I have a method whose purpose is to delete the values from one array (a1)
> from another array (a2).
> So I
>
>    1. Sort both arrays
>    2. Loop through the the array containing the values (a1) to be deleted
>    1. Use Find in Array to see if the value in a1 is present in a2
>          1. If yes, use Count in Array to determine the number to be
>          deleted
>          2. Use DELETE FROM ARRAY to the number of elements found
>
> I have found situations in v13.3, v13.6 and v15.0 where the number of
> elements counted in step 2.1.1 does not match the Debug windows display of
> the array.
>
> The basic code is below. And it works at least 90% of the time.
>
> Any ideas would be appreciated! I have written a replacement for this
> function but I am having a hard time believing that something this basic
> doesn't work...
>
> Thanks,
> Alan Tilson
>
> $pAr_DeleteFrom:=$1
> $pAr_ValuesToDelete:=$2
> $count_i:=$3
>
> SORT ARRAY($pAr_DeleteFrom->;>)
> SORT ARRAY($pAr_ValuesToDelete->;>)
>
> $start:=0
> For ($el;1;Size of array($pAr_ValuesToDelete->))
>
> $_ValueToDelete:=$pAr_ValuesToDelete->{$el}
> $start:=Find in array($pAr_DeleteFrom->;$_ValueToDelete;$start)
> If ($start=-1)
>
> $start:=0
>
> Else
>
> $count_toDelete:=Count in array($pAr_DeleteFrom->;$_ValueToDelete;$start)
>
> DELETE FROM ARRAY($pAr_DeleteFrom->;$start;$count_toDelete)
>
> End if
>
> End for
>
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