Hi
But Thats what I'm doing, and its not working.

The string looks like "12345.12345" and the Conversion looks like

C_REAL($Number)
C_TEXT($NumString)
$NumString:-"12345.12345"
$Number:=Num($NumString;".")

On a UK system $Number = 12345.12345
On a German system $Number = 12345

any ideas would be very welcome
Im considering using replace string on $numString to replace "." with the
local separator, in this case ","

thanks
-pm

On Wed, Dec 13, 2017 at 2:32 AM, Chuck Miller via 4D_Tech <
4d_tech@lists.4d.com> wrote:

> Much better than my choice which was substring till the period and then num
>
> Regards
>
> Chuck
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> > On Dec 12, 2017, at 7:22 PM, Keisuke Miyako via 4D_Tech <
> 4d_tech@lists.4d.com> wrote:
> >
> > the second "separator" argument for Num() has existed and has been a
> "must use" feature since v11 for i18n.
> >
> > http://doc.4d.com/4Dv16/4D/16.3/Num.301-3651255.en.html <
> http://doc.4d.com/4Dv16/4D/16.3/Num.301-3651255.en.html>
>
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