Hi Ferdinando,
schematicaly:
selection to arrays (ID, name, surname, date of birth, sex)
for($i;size of array;1;-1)
if (values $i # values $i-1)
remove from arrays
end if
end for
query with array (arrayIDs)
and you have the duplicates
--
Arnaud
> Le 22 oct. 2022 à 12:04, stardata.info via 4D_Tech <4d_tech@lists.4d.com> a
> écrit :
>
> Hi All,
>
> I use 4D V16, and in one application i need to find all patient that have the
> same name, surname, date of birth, sex.
>
> Someone have already do this feature?
>
> Thanks
>
> Ferdinando
**********************************************************************
4D Internet Users Group (4D iNUG)
New Forum: https://discuss.4D.com
Archive: http://lists.4d.com/archives.html
Options: https://lists.4d.com/mailman/options/4d_tech
Unsub: mailto:4d_tech-unsubscr...@lists.4d.com
**********************************************************************
