A short IEEE 802.15.4 address is 16 bits in length. Short addresses
are mapped into the restricted space of IEEE EUI-64 addresses by
setting the middle 16 bits to 0xfffe, the bottom 16 bits to the short
address, and all other bits to zero. As a result, an IID generated
from a short address has the form:
0000:00ff:fe00:XXXX
Doesn't this section cause problems with the Xerox OUI? If I have a
Xerox Ethernet card with a 48b MAC address of 0x1 it will generate a
link local address of fe80::ff:fe00:0001 when the 48b address is
expanded to 64b. An 802.15.4 short address will generate the same link
local address. Now I doubt that any of the first 64K Ethernet
addresses are still in use, but to keep everything truly unique
shouldn't there be an IEEE assigned OUI for 802.15.4 short addresses?
http://standards.ieee.org/regauth/oui/index.shtml
With a 24b OUI assigned the whole 64b address space become usable. For
example aaaa:aa00:panid:short where aaaaaa is the OUI. The OUI of
80:21:54 hasn't been assigned, it would be a good choice.
--
Jon Smirl
[email protected]
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