Hi Remy, I think this can be an implementation decision. IMHO, when a node requests a relocation like the one in Figure 15, it assumes that any of the candidate cells is equivalent. This means that if [1,2] cannot be relocated then [2,2] won't be able too. Seen in another way, the relocation may happen in the list order consuming all possible candidate cells. This can be seen as a policy that may depend on the implementation or SF rules so other options may also be possible but are out of the scope of 6P..
Do you have a specific example where the case you present is relevant? regards, Xavi 2017-08-30 8:29 GMT+02:00 Liubing (Remy) <[email protected]>: > Hello folks, > > I have a question about the relocation of cells in the draft > 6tisch-6top-protocol. > > In section 4.3.3, node A wants to relocate several cells and selects > candidate cells from its schedule for node B, then node B's SF verifies > which of the cells it can install in its schedule. The verification can be > partially succeed. If N < NumCells cells appear in the CellList, this means > first N cells in the Relocation CellList have been relocated, the remainder > have not. > > Does this mean that if the relocation of the first cells fails, there > would not be necessary to verify if the rest cells could be relocated? For > example, in Figure 15, if the cell (1,2) in the R. CellList cannot be > relocated to any of the cells in C.CellList, then (2,2) will not be > relocated even if it is possible to relocate it to (6,5)? > > Thanks, > > Remy > > _______________________________________________ > 6tisch mailing list > [email protected] > https://www.ietf.org/mailman/listinfo/6tisch > -- Dr. Xavier Vilajosana Wireless Networks Lab *Internet Interdisciplinary Institute (IN3)Professor* (+34) 646 633 681 [email protected] <[email protected]> http://xvilajosana.org http://wine.rdi.uoc.edu Parc Mediterrani de la Tecnologia Av Carl Friedrich Gauss 5, B3 Building 08860 Castelldefels (Barcelona). Catalonia. Spain [image: Universitat Oberta de Catalunya]
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