On Mon, Oct 20, 2008 at 10:11:22PM +0100, Charles Forsyth wrote: > >Forgive my ignorance, but I don't see how the code in question relates to > >returning a 64-bit value? > MOVL a+0(FP),CX > MOVL AX,0(CX) > MOVL AX,4(CX) > > that's how a 64-bit value is returned on 32-bit machines: > similar to returning a structure, the caller passes a > hidden first argument referring to the 64-bit return location. > in this case, since -1 is already in AX, storing that in both 32-bit > parts of the 64-bit value produces -1LL
Oh interesting. Thanks for the clarification. I had thought 64 bit returns were done in %eax and %edx. Sorry for the noise. --nwf;
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