Thanks martin for your analysis, this makes some sense to me, but as I
pointed out, even setting ifs to () doesn't solve the issue, so it
would be nice to find a solution to this.
Right now having the output of `{} corrupted can be quite inconvenient...
Thanks
uriel
On Tue, Mar 17, 2009 at 3:01 AM, Martin Neubauer <[email protected]> wrote:
> On second thought (and in the light of Geoffs reply) I probably won't.
> If you do care, the following change to the loop in question will at
> least preserve all input:
>
> while((c = rchr(f))!=EOF){
> if(strchr(stop, c)){
> if(s!=wd){
> *s='\0';
> v = newword(wd, v);
> s = wd;
> }
> }
> else if(s==ewd){
> *s='\0';
> v = newword(wd, v);
> s = wd;
> *s++=c;
> }
> else *s++=c;
> }
>
> With a dynamic buffer the tokenisation could be prevented, but in your
> example the lexical scanner would quite likely bail afterwards. (I
> remember a discussion some time ago about this.)
>
>
