I think
awk '{$1="";print}'
should do what you want, provided that you don't care about leading spaces.2009/11/19 Peter A. Cejchan <[email protected]>: > On Thu, Nov 19, 2009 at 9:52 AM, Russ Cox <[email protected]> wrote: >> awk '{print substr($0, 1+length($1)+1)}' >> > > Big thank you, Russ, however, wouldn't it be smarter if we had some > kind of 'not' operator here...? Sometimes, especially when you write > the script by hand it is easier to delete few fields than to > explicitly write out all those remaining... IMHO... > > ++pac > > -- Hugo
