> and without use flags I end up having k*m packages instead of m. So the
> question still comes to do I write it to allow 2^n^m possible combinations
> and document the two most common scenarios, or write 2*m package variants
> and leave it to the interested to populate any of the remaining 2^{k-2}
> permutations. I'm still undecided, but I know then kinds of bugs that
> creep up when splitting trees like that. (I guess like splitting hairs ;-)
at a minimum, ditch the use flags.
these complications are why i decided it
would be easier to just do 9atom.
- erik
