Sorry to bother the list, but I thought I might get a sensible answer
here from the few remaining people in the world who actually
understand C.
The following bit of code seems to be more or less syntactically OK:
switch (nurdge)
{
int nigel = 1;
case 0:
if(nigel == 1)
printf("nigel is one.\n");
else
printf("nigel is not one.\n");
default:
printf("The value of nigel is %d", nigel);
}
Something close to this compiles under my C compiler, and yet the
variable "nigel" is not initialised, and the test inside the first
case test is pretty much certain to print "nigel is not one". Although
my C++ compiler does complain about an uninitialised variable.
I'm puzzled as to why the line "int nigel = 1;" is syntactically OK,
and although it seems to have declared the variable "nigel" - else the
following code would fail to compile - has failed to give it the
initial value of 1, as requested.
