On Mon Nov 26 04:56:23 EST 2012, [email protected] wrote:
> The message is:
>
> (2050) DATA opnames<1>+116(SB)/4,$string<1>+739(SB)
> memccpy: multiple initialization
> (2170) DATA etnames<1)+72(SB)/4,$string<1>+912(SB)
> memccpy: multiple initialization
>
> I know 2050 is somehow related to the line number where opnames appear in the
> code, and so is 2170 with etnames.
> I know it's suggesting I had an opnames initialized some where, but I just
> don't know where to look. I read the 8l man, but it seems there is no other
> docs where I can check for detail information.
> Can anybody tell me what the rest number of the message means, where should I
> look for the duplicate code?
this is the format from 8l/list.c:/^Pconv
snprint(str, sizeof(str), "(%ld) %A %D,%D",
p->line, p->as, &p->from, &p->to);
it looks like memccpy is defined twice in the same .8.
i'd look for the symbol rather than the line number.
the format of the line number doesn't fit the plumbable
convention, which would be file:line, and also appears to
not be the line number you are expecting. it's
the line number after include files are processed. which
while not wrong, is not helpful either.
- erik
---
example:
; cat mdef.c
#include <u.h>
#include <libc.h>
void
x(void)
{
}
void
x(void)
{
}
void
main(void)
{
}
; tmk mdef.c
6c -FVTw mdef.c
6l -o 6.mdef mdef.6
x: mdef.6: redefinition: x
(818) TEXT x+0(SB),$0
; # modified 8c to output line numbers in comments
; /sys/src/cmd/8c/6.out -S mdef.c
TEXT x+0(SB),0,$0 /* 806 */
RET , /* 808 */
TEXT x+0(SB),0,$0 /* 811 */
RET , /* 813 */
TEXT main+0(SB),0,$0 /* 816 */
RET , /* 818 */
END , /* 818 */
