> On 4 April 2013 20:50, erik quanstrom <quans...@quanstro.net> wrote: > > > so > > i think this assumption is going to lead to > > 6-byte buffer overruns. > > > > I don't follow the reasoning. bufsize + Rread or Twrite will always fit. > bufsize is the limit for application data. The receiving 9P also trims the > count > to match the receiving buffer.
i'm thinking of applications that have a seperate buffer for data. in this case, i can't think of a clean way of sizing that seperate buffer correctly. if msize=bufsize+IOHDRSZ, then incoming bytes would be too big. - erik
