On 13 September 2015 at 19:46, <[email protected]> wrote:
> so we really want to have n->type == double/float
no, it happens to be wrong for ordinary integers too:
int
x(int a, double d)
{
a += (a += d);
return a;
}
should have the outer += done as int using the result of a += d as stored
back into `a' and read back,
but instead it incorrectly does two floating-point adds. it evidently isn't
that common to feed the result
of += etc back into a computation, at least with mixed modes, or this would
have been more troublesome.
