I see in tlshand.c in libsec:
// get current hash value, but allow further messages to be hashed in
sha2_256(nil, 0, seed, &hsh.sha2_256);
I assume passing nil and 0 allows the hashing function to just dump the current
hash in seed in our case.
I also assume multiple calls with nil and 0 will return the same value.
It doesn't!
Calling sha2_256 with nil and 0 again returns a different value.
Am I misunderstanding the behavior or is this just incomplete?
Test program:
#include <u.h>
#include <libc.h>
#include <libsec.h>
void
main(void)
{
uchar d1[SHA2_256dlen], d2[SHA2_256dlen], d3[SHA2_256dlen], s1[] = "hello,",
s2[] = "world";
DigestState s;
int i;
sha2_256(s1, 6, nil, &s);
sha2_256(s2, 5, d1, &s);
print( "main: 1st call: d1: \n");
for(i = 0; i < SHA2_256dlen; i++) {
print("%02x", d1[i]);
}
print("\n");
sha2_256(nil, 0, d2, &s);
print( "main: 2st call: d2: \n");
for(i = 0; i < SHA2_256dlen; i++) {
print("%02x", d2[i]);
}
print("\n");
sha2_256(nil, 0, d3, &s);
print( "main: 3rd call: d3: \n");
for(i = 0; i < SHA2_256dlen; i++) {
print("%02x", d3[i]);
}
print("\n");
exits(0);
}
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