Russ Cox <[EMAIL PROTECTED]> writes | but that won't actually have any effect on systems where | int is 32 bits but long is 64. the problem is that ((p)[3]<<24) | is being (correctly) treated as a signed int, and then | (vlong)(...|((p)[3]<<24)) sign extends. Casting the (p)[0] | to (ulong) has the effect of making the whole 32-bit expression | unsigned on 32-bit systems, but if ulong is 64 bits, then | you'll still sign-extend ((p)[3]<<24) during the convertsion | from int to ulong.
i'll be wearing the dope sack over my head this week. - erik
