On Sat Jul 15 07:37:29 CDT 2006, [EMAIL PROTECTED] wrote:
> > your loop test has an obiwan error:
> >
> > for(i=0;i <= inbyterate;i++) {
> >
> > should be
> > for(i = 0; i < inbyterate; i++);
> >
>
> heh.. 'oups' ;) .. Thanks Erik. Nevertheless, that is not the problem. Do you
> have an idea why acid does not 'see' i ? Or how I can investigate i?
i = j/2. i'm still pretty sure that kenc is optimizing i away. here's what i'd
do. if samplerate is large (~10000), you need to make sure that data and
datacopy
are not on the stack. then run acid on the broken process and make sure you're
actually on the line expected and use i = j/2 to figure out what i is.
- erik
