If I remember my rainbow tables basics, 2^28.5 chains * 2^8.5 tables will be just around 2.199TB ? How much for a >95% success rate? Before I go read the paper again and figure it out myself, is there already a page where this math is detailed on the wiki?
Thanks, EiNSTeiN_ On Fri, 2009-09-11 at 17:46 +0200, Sascha Krissler wrote: > When reach our initial goal of 2^8.5 tables with 2^28.5 unique chains each, > we would get a probability > of around 50%, so at some point this would be the actual probability. It is > not unlikely that people will carry > on generating, increasing this probability and also increasing the lookup > speed. > > > suppose the community build all the tables then how much is our success > > chance to crack a given recorded conversation ? > > > > > > <hr> > > _______________________________________________ > > A51 mailing list > > [email protected] > > http://lists.lists.reflextor.com/cgi-bin/mailman/listinfo/a51 > > > > > > > ________________________________________________________________ > Neu: WEB.DE Doppel-FLAT mit Internet-Flatrate + Telefon-Flatrate > für nur 19,99 Euro/mtl.!* http://produkte.web.de/go/02/ > > _______________________________________________ > A51 mailing list > [email protected] > http://lists.lists.reflextor.com/cgi-bin/mailman/listinfo/a51 _______________________________________________ A51 mailing list [email protected] http://lists.lists.reflextor.com/cgi-bin/mailman/listinfo/a51
