Chris Snyder writes:
>
> Dumb-ass answer:
>
> print "Number to square: ";
> $num = <STDIN>;
>
> print $num ^ 2, "\n";
>
> I haven't tested this, but you get the idea.
That operator is bit-wise exclusive or. I think the OP was looking for
exponentiation which is rather different (** operator BTW). For more
operator info see 'perldoc perlop'.
HTH
--
Brian Raven
So far we've managed to avoid turning Perl into APL. :-)
-- Larry Wall in <[EMAIL PROTECTED]>
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