Actually... for simplicities sake drop the + modifier and just negate the
result. A read of 'Mastering Algorithms with Perl' will also reveal that
for static string matches you get better performance (not that I've
benchmarked it myself, I just trust the text) from index().
$string !~ /\s/
not $string =~ /\s/
-1 == index $string, ' ' # faster than a regex, only works for the
literal value ' '. \s matches more white-space characters.
Josh
"$Bill Luebkert" <[EMAIL PROTECTED]>
Sent by: [EMAIL PROTECTED]
07/18/2002 07:14 AM
To: "Martin, Greg \(CSC\)" <[EMAIL PROTECTED]>
cc: "'[EMAIL PROTECTED]'"
<[EMAIL PROTECTED]>
Subject: Re: Regex - matching a string with no spaces
Martin, Greg (CSC) wrote:
> If there's a better place to post this, please let me know.
>
> I'm trying to write a module that looks at mailbox names and excludes
> non-people. I use regex to match specific strings which I no are not
> people, but I'd like a generic regex to match strings which have no
spaces
> (a common indicator of non-human mailboxes). This should be easy and
I've
> tried several things but just can't get through the mental block
>
> My feeble tries:
> [^\s] (matches every non-space character)
> [\s{0}] (0 occurrences of set \s - excludes everything apparently)
> \s{0} (0 occurrences of \s - same thing)
If I understand your question (you really should post a code snippet):
if ($str =~ /\s+/) {
# string has whitespace
}
# or for just spaces/blanks rather than ' ', \t, \n try: if ($str =~ /
+/) {
# \s means whitespace not space/blank
--
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