RE: counting differently

[Bussink, Pim GJ SUKEP-EPE-T-D]

Cliff,   maybe as a Perl (but not programming) novice I am missing your point / application, but one could of course create an array @letter = (a..z) and walk through that, or if you are into Object Orientation create a letter class with a next() member function that knows the alphabet.   By the way, a question of mine: could one overload the ++ operator (which I like better than Cliff's '+ 1') instead of this next() above, by the way, such that $letter = 'a'; $letter++ gives you 'b'?  I guess you ned to hack the code for that?  Far-fetched perhaps...  Oh well.   Cheers, Pim -----Original Message----- From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] Sent: 23 February 2004 14:52 To: [EMAIL PROTECTED] Subject: counting differently Is there a way to force a variable to walk through the alphabet the way it can numbers?   ie: for numbers:  $k=0; $k=$k+1; would give you 1   for letters $k='a'; $k=$k+1; this won't give you 'b'; but is there any way of doing this that will?

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