From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] On Behalf Of
[EMAIL PROTECTED]
Sent: 20 February 2006 14:13
To: John W. Kennedy
Cc: activeperl mailing list
Subject: Re: Was I dreaming? Using keys(%hash) as lvalue
> Idle curiosity prompts me to pose this conundrum: what happens if I
set keys() *at* a power of two? That is, if > I do
>
> keys(%hash) = 256;
>
> will I get 256 buckets? Or 512?
Try it and see:
my %h;
print scalar(%h), "\n";
$h{a} = 1;
print scalar(%h), "\n";
keys %h = 256;
print scalar(%h), "\n";
$h{$_}=$_ for 'a'..'zzz';
print scalar(%h), "\n";
See 'perldoc perldata' under "Scalar values".
HTH
--
Brian Raven
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