Wayne Simmons wrote:
> From: Wayne Simmons
> >
> > my $x = .0006;
> > my $y = $x * 10000;
> > print $y , "\n";
> > print sprintf("%04d\n",$y);
> > print int($y), "\n";
> > __END__
>
> From: Christopher Hahn [mailto:[EMAIL PROTECTED]
> >
> > Int returns the integer portion --> it truncates!
>
>
> Great, thanks for filling me in! So 6 truncates to 5 in perl?!? :-0
No, 5.9999999999999991118215803 truncates to 5 in most any language.
The problem is that floating point calculations are always
approximate in computers.
This may make more sense:
my $x = .0006;
my $y = $x * 10000;
print "Number looks like this: $y\n";
printf "But it is really this: %0.25f\n", $y;
printf "And it truncates to this: %d\n",$y;
Output:
Number looks like this: 6
But it is really this: 5.9999999999999991118215803
And it truncates to this: 5
--
Bowie
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