In general, an interface "inheriting" for any type isn't supported. An interface can only "implement" another interface. There's no way to constrain a type parameter to "interfaces".
Then, of course, you can't use a type parameter as a base class/interface anyway... =================================== This list is hosted by DevelopMentor® http://www.develop.com View archives and manage your subscription(s) at http://discuss.develop.com
