The problem is that I have to multiply by 100 before rounding, so the double
must no be off by more than 0.005. For example, if 4.56 is actually stored
as 4.5610, the number multiplied by 100 will be 456.100 which gets to
456.600 when adding 0.5 which rounds up to 457.

I feel like my brain is about to explode...


-----Original Message-----
From: Discussion of advanced .NET topics.
[mailto:[EMAIL PROTECTED] Behalf Of Terry Griffin
Sent: Monday, August 25, 2008 1:27 PM
To: ADVANCED-DOTNET@DISCUSS.DEVELOP.COM
Subject: Re: [ADVANCED-DOTNET] Converting doubles into integers without
rounding errors


The problem with going from a double to an int is that the final digit can
be cut off because the double is inexact. But the double will be close.
All you need to do is add 0.5 to the value before doing the conversion to
an int. The "extra" 0.5 will make a value like 4.999999999 get converted
to 5 instead of 4. Unless your original numbers are off by a large amount
(close to 0.5) this won't introdcue any error.

int intVal;
double dblVal;

intVal = (int)(dbleVal * 100 + 0.5);



Terry Griffin
Sr. Software Engineer
Carl Zeiss SMT Inc.
ALIS Business Unit
1 Corporation Way
Peabody, MA 01960 USA
[EMAIL PROTECTED]
(978) 826-1569




Daniel Barla-Szabo <[EMAIL PROTECTED]>
Sent by: "Discussion of advanced .NET topics."
<ADVANCED-DOTNET@DISCUSS.DEVELOP.COM>
08/25/2008 01:10 PM
Please respond to
"Discussion of advanced .NET topics."
<ADVANCED-DOTNET@DISCUSS.DEVELOP.COM>


To
ADVANCED-DOTNET@DISCUSS.DEVELOP.COM
cc

Subject
Re: [ADVANCED-DOTNET] Converting doubles into integers without rounding
errors






Personally, I've never used it before, but I see in framework 2.0 there is
the option of:

(int) Double.Truncate(objMyObject.Amount * 100);

HTH

-----Original Message-----
From: Discussion of advanced .NET topics.
[mailto:[EMAIL PROTECTED] On Behalf Of Eddie Lascu
Sent: 25 August 2008 06:28 PM
To: ADVANCED-DOTNET@DISCUSS.DEVELOP.COM
Subject: [ADVANCED-DOTNET] Converting doubles into integers without
rounding
errors

Hello everyone,

I have some objects that contain an amount field that is declared as
double.
Since it contains amounts, it always has only two decimal digits that are
significant. During the process I need to convert that double into an
integer by removing the decimal point. For example, $78.59 should be
converted to integer 7859 and $101.53 to 10153. in my code I have
uint nIntAmount = (uint)(objMyObject.Amount * 100);

The problem I am facing is that sometimes, very rarely, there is a
rounding
error that is introduced and the integer obtained is off by a cent (plus
or
minus). For example, this is a line that was traced in my log file:

"Updating the batch with $137.89 as the amount in the transaction. This
amount was converted to 13788."

Can either of you suggest a different way to convert the amounts in
integers
without this nagging rounding error?

Any help will be appreciated,

Eddie

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