RE: JTable row renderer

Bhangale, Bhushan Tue, 03 Sep 2002 09:19:34 -0700

Title: Message

Following is a prepare Renderer method which I am writing after subclassing the JTable class. But this doesn't work properly. When I select the row only at that time it shows the proper color.

public Component prepareRenderer(TableCellRenderer renderer, int row, int column) {
Component component = super.prepareRenderer(renderer, row, column);

Long longTime = (Long) logMessageTableModel.getValueAt(row, 4);
Object value = logMessageTableModel.getValueAt(row, column);

   if (null != longTime && ((System.currentTimeMillis() - longTime.longValue()) <= highlightDuration)) {
    component.setBackground(Color.cyan);
   }
   else if (1 == column && null != value) {
    String strValue = value.toString();

    if (strValue.equalsIgnoreCase("FATAL")) {
     component.setBackground(Color.red);
    }  else {
     component.setBackground(null);
    }
   }
   else {
    component.setBackground(null);
   }

return component;
}

Following is the code where I have created my Table Cell renderer. This works fine. In this I need to register the renderer for all the colums.

JTable logMessageTable = new JTable();

ColoredTableCellRenderer coloredTableCellRenderer = new ColoredTableCellRenderer();
logMessageTable.getColumn(VTBrokerClient.logMessageTableColumnNames[0]).setCellRenderer(coloredTableCellRenderer);
logMessageTable.getColumn(VTBrokerClient.logMessageTableColumnNames[1]).setCellRenderer(coloredTableCellRenderer);
logMessageTable.getColumn(VTBrokerClient.logMessageTableColumnNames[2]).setCellRenderer(coloredTableCellRenderer);
logMessageTable.getColumn(VTBrokerClient.logMessageTableColumnNames[3]).setCellRenderer(coloredTableCellRenderer);

class ColoredTableCellRenderer extends DefaultTableCellRenderer {
public Component getTableCellRendererComponent (JTable table, Object value, boolean selected, boolean focused, int row, int column) {

Long longTime = (Long) logMessageTableModel.getValueAt(row, 4);

   if (null != longTime && ((System.currentTimeMillis() - longTime.longValue()) <= highlightDuration)) {
    setBackground(Color.cyan);
   }
   else if (1 == column && null != value) {
    String strValue = value.toString();

    if (strValue.equalsIgnoreCase("FATAL")) {
     setBackground(Color.red);
    }  else {
     setBackground(null);
    }
   }
   else {
    setBackground(null);
   }

super.getTableCellRendererComponent(table, value, selected, focused, row, column);

return this;
}
}

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RE: JTable row renderer

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