3 degrees at 30 miles 360 degrees in a circle so 3 degrees is 120th of that. Circumference = Pi x Diameter 188 miles = 3.14....X 60 188 miles / 120 = 1.57 Miles. You should divide that in half since you are probably pointed to the middle of the signal so maybe 3/4 of a mile wih no safety margin at thirty miles. Just divide that by the % of distance to get other distances.
On Fri, Dec 2, 2016 at 2:37 AM TJ Trout <[email protected]> wrote: > Can someone tell me the width of a 5ghz signal at 30 miles coming from a > 3* or 5* antenna? > > On Thu, Dec 1, 2016 at 10:48 PM, That One Guy /sarcasm < > [email protected]> wrote: > > radiomobile or link planner (just get systems in play with "close enough" > characteristics on the links) and move the sites then recalculate til you > hit your unacceptable margins > > On Thu, Dec 1, 2016 at 11:17 PM, TJ Trout <[email protected]> wrote: > > I have a tower site which customers are connected from a distance of 18-45 > miles away ( remote mountain) I'm using 5ghz with 120* sectors. Customers > are using rcl-2 and 2ft parabolic antennas. > > Any ideas how to calculate how far I can relocate the sectors without > having to realign the customers antennas ? > > Thanks > > -- > If you only see yourself as part of the team but you don't see your team > as part of yourself you have already failed as part of the team. > >
