I tried encode.su many times but shelwien is reading my post like chinese bro 
haha even after being clear, I better ask you for once ok.

http://mattmahoney.net/dc/dce.html#Section_58

See where you say:
"They use partial update exclusion. When a character is counted in some 
context, it is counted with a weight of 1/2 in the next lower order context. 
Also, when computing symbol probabilities, it performs a weighted averaging 
with the predictions of the lower order context, with the weight of the lower 
order context inversely proportional to the number of different higher order 
contexts of which it is a suffix."

Please let me explain. What I'm talking about is the idea of windowing the 
prompt ex. [i[ [w[a[s[ [e[a[t[i[n[g[ [a[ ]]]]]]]]]]]]]]] and when you window 
shorter views you get lots more stats right, so, some of the ones in the longer 
higher order are IN the shorter ones, just a few, but still, so I think others 
are saying to give these few "sames" in the lower order windows 0.5% the weight 
since we already seen the predictions from longer windows on the prompt. BUT, 
if we apply global weights to orders - or handle the weighting using an 
automatic criteria instead of manual static mix weights, we need not remove 
0.5% weight on shorter windows's same predictions if give the higher order less 
weight correctly in the first place. Seeing this, I don't have to code this 
idea, since it is the same thing...

For example what I do in mine is if I search for the last 17 letters and get 
only 3 predictions (it doesn't know other letters can follow yet), the roof for 
counts needed is lower for example, hence, if i have just 66 counts and 3 
unique predictions, I may have captured the distribution - perhaps only 3 
different kinds of predictions come next! The rest are so rare it's not 
required to see them. Maybe we are confident here. Hence, I know how much 
weight to give the 16th order predictions. It's all about order 16, not order 
16's that appear IN order 15 counts predicted, we simply finish it all in order 
16.

Right?
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