Well, taking the scores above (ex. 0.5505...) (the part failed at and "have to
store" hence 1.0 - 0.5505...) gives me a number like 45,000,000, which is how
many letters of storage of the full 100MB text to store then ("my _loss" or
"failure" to be clear)....and it * 0.4152375 (shannon and weaver's number
saying you can at most compress a random number to bin form to represent that
random number) gives me similar numbers....:
10MB 18,660,980
1MB 19,474,364
100KB 21,969,003
10KB 22,172,079
10MB should be about 2,207,890.....but at least it's doing better right ????????
Will keep thinking on this now.
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Artificial General Intelligence List: AGI
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