The problem is much easier given two lists
; Premise code (c) 2014 Michael S P Miller
function list-similarity {?A ?B}
(put (+ (length (intersection ?A ?B)) 1) ?LenAnB)
(put (+ (length (difference ?A ?B)) 1) ?LenA-B)
(put (+ (length (difference ?B ?A)) 1) ?LenB-A)
(put (+ (length ?A) 1) ?LenA)
(put (+ (length ?B) 1) ?LenB)
(return
(* 0.5 (- (+ (/ ?LenAnB ?LenA) (/ ?LenAnB
?LenB))
(+ (/ ?LenA-B ?LenA) (/ ?LenB-A
?LenB))))end
For numbers, it's a little more difficult.
Your thoughts?
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AGI
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