On Wed, Oct 8, 2008 at 5:15 PM, Abram Demski <[EMAIL PROTECTED]> wrote:
> Given those three assumptions, plus the NARS formula for revision, > there is (I think) only one possible formula relating the NARS > variables 'f' and 'w' to the value of 'par': the probability density > function p(par | w, f) = par^(w*f) * (1-par)^(w*(1-f)). Note: NARS > truth values are more often (I think?) represented by the pair 'f' > 'c', where 'c' is computed from 'w' by the formula c=w/(w+k), where k > is a fixed constant. This is of little consequence at this point, and > it was more intuitive to use 'f' and 'w' (at least for me). At this stage, you are right. Since c and w fully determines each other, in principle you can use either, and w is more intuitive. However, in designing the truth-value functions, it is more convenient to use c, a real number in [0, 1], than w, which has no upper bound. > Here's the math. In NARS, the operation we're interested in is taking > two pools of evidence, one concerning A=>X and the other concerning > B=>X, and combining them to calculate the evidence they lend to A=>B. Now things get tricky, In my derivation, in abduction/deduction the evidence of a premise is not directly used as evidence for the conclusion. Instead, it is the premise, as a summary of its own evidences, that is used as evidence. That is, X is not a set, but an individual. Consequently, the operation doesn't "taking two pools of evidence" and somehow combine them into one pool (as in the revision rule). > So probabilistically, we want to determine the probability of the > evidence for A=>X and B=>X given each possible 'par' value of A=>B. According to the semantics of NARS, A=>X or B=>X, by itself, doesn't provide evidence for A=>B. Overall, it is a nice try, but given the difference in semantics between probability theory and NARS, I'm still doubtful on how far you can go in this direction. Pei ------------------------------------------- agi Archives: https://www.listbox.com/member/archive/303/=now RSS Feed: https://www.listbox.com/member/archive/rss/303/ Modify Your Subscription: https://www.listbox.com/member/?member_id=8660244&id_secret=114414975-3c8e69 Powered by Listbox: http://www.listbox.com
