> From: Matt Mahoney [mailto:[EMAIL PROTECTED] > > --- On Thu, 10/30/08, John G. Rose <[EMAIL PROTECTED]> wrote: > > > You can't compute the universe within this universe > > because the computation > > would have to include itself. > > Exactly. That is why our model of physics must be probabilistic > (quantum mechanics). >
I'd venture to say that ANY computation is an estimation unless the computation is itself. To compute the universe you could estimate it but that computation is an estimation unless the computation is the universe. Thus the universe itself IS an exact computation just as a chair for example is an exact computation existing uniquely as itself. Any other computation of that chair is an estimation. IOW a computation is itself unless it is an approximation of something else, it's somewhere between being partially exact or a partially exact anti-representation. A computation mimicking another same computation would be partially exact taking time and space into account. Though there may be some subatomic symmetric simultaneity that violates what I'm saying above.... not sure. Also it's early in the morning and I'm actually just blabbing here so this all may be relatively inexact :) John ------------------------------------------- agi Archives: https://www.listbox.com/member/archive/303/=now RSS Feed: https://www.listbox.com/member/archive/rss/303/ Modify Your Subscription: https://www.listbox.com/member/?member_id=8660244&id_secret=117534816-b15a34 Powered by Listbox: http://www.listbox.com
