Hello,
If you do the following:
future1 map { r => agent.send(1) }
future2 map { r => agent.send(2) }
The order of the sends will be determined by the length of future1 and
future2.
I would expect something like
agent.sendOff(future1 map { r => 1 })
agent.sendOff(future2 map { r => 2 })
In a way the sends are applied in order.
Regards,
partycoder
On Thursday, February 13, 2014 3:43:14 AM UTC-8, rkuhn wrote:
>
> Hi partycoder,
>
> in which way does your code cause an ordering problem? What do you observe
> and why is that not as it should be?
>
> Regards,
>
> Roland
>
> 12 feb 2014 kl. 06:36 skrev [email protected] <javascript:>:
>
> Hello,
>
> I have a question.
>
> val f = some future
> val a = Agent(some type)
>
> // This may cause an ordering problem
> f map { result => a.send(result) }
>
> How do I use agent.send/sendOff using futures?
>
> Regards
>
> --
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>
> *Dr. Roland Kuhn*
> *Akka Tech Lead*
> Typesafe <http://typesafe.com/> – Reactive apps on the JVM.
> twitter: @rolandkuhn
> <http://twitter.com/#!/rolandkuhn>
>
>
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