Hi Endre, thanks for your quick reply.
About your first recommendation, I do not have to work with any legacy
code. So, If I am not supossed to use an appserver, what am I supossed to
do?
Abour your second recommendation. I create the actor system and also the
actors inside a servlet, but I do it only one time, like this:
ServletContext application =
request.getSession().getServletContext();
ActorSystem actorSystem = null;
if (application.getAttribute("auctionSystem") == null)
{
//Create the actor system
actorSystem = ActorSystem.create("auctionSystem");
application.setAttribute("auctionSystem", actorSystem);
} else
{
actorSystem = (ActorSystem)
application.getAttribute("auctionSystem");
}
So, it will be created only once, doesn't it?
About your third recommendation. Why am I not supossed to use akka inside a
servlet. I use the servlet only to get an actor reference and then to send
a message to the actor I want, is it a wrong approach? and what do you mean
by standalone application with akka?
Cheers,
On Wednesday, June 18, 2014 9:39:38 PM UTC+10, Akka Team wrote:
>
> Hi Felipe,
>
>
>> - Akka 2.3.2 (How can I deploy it on glassfish?)
>>
>>
> Akka does not support deploying to application servers, although it is
> possible to make it work. Unless you have to work with legacy code I would
> completely avoid going through an appserver completely.
>
>
>>
>> [2014-06-18T06:30:50.261+0000] [glassfish 4.0] [INFO] [] [] [tid:
>> _ThreadID=224 _ThreadName=Thread-3] [timeMillis: 1403073050261]
>> [levelValue: 800] [[
>> [ERROR] [06/18/2014 06:30:50.245] [http-listener-1(4)] [Remoting]
>> Remoting error: [Startup failed]
>> akka.remote.RemoteTransportException: Startup failed
>> at
>> akka.remote.Remoting.akka$remote$Remoting$$notifyError(Remoting.scala:128)
>> at akka.remote.Remoting.start(Remoting.scala:193)
>> at
>> akka.remote.RemoteActorRefProvider.init(RemoteActorRefProvider.scala:184)
>> at akka.actor.ActorSystemImpl.liftedTree2$1(ActorSystem.scala:617)
>> at akka.actor.ActorSystemImpl._start$lzycompute(ActorSystem.scala:615)
>> at akka.actor.ActorSystemImpl._start(ActorSystem.scala:615)
>> at akka.actor.ActorSystemImpl.start(ActorSystem.scala:632)
>> at akka.actor.ActorSystem$.apply(ActorSystem.scala:141)
>> at akka.actor.ActorSystem$.apply(ActorSystem.scala:108)
>> at akka.actor.ActorSystem$.create(ActorSystem.scala:56)
>> at akka.actor.ActorSystem.create(ActorSystem.scala)
>> at
>> Control.servletForwarderUserRegFirstStep.doPost(servletForwarderUserRegFirstStep.java:39)
>> at javax.servlet.http.HttpServlet.service(HttpServlet.java:707)
>> at javax.servlet.http.HttpServlet.service(HttpServlet.java:790)
>>
>
> Looking at the snippet above it seems that you try to create the
> ActorSystem from a servlet, especially from it service method. That will
> try to create a new ActorSystem every time a request is serviced, so it
> will fail to bind to the same address.
>
> So first of all, you should only create one ActorSystem in your
> application and use that all the time instead of creating a new one every
> time. Second, you should not use Akka from servlets, you can just build
> standalone applications with Akka.
>
> -Endre
>
> --
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>
>
> --
> Akka Team
> Typesafe - The software stack for applications that scale
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>
--
>>>>>>>>>> Read the docs: http://akka.io/docs/
>>>>>>>>>> Check the FAQ:
>>>>>>>>>> http://doc.akka.io/docs/akka/current/additional/faq.html
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