I still don't understand, if we have 2 unbounded streams, how do we sort
them without consuming all of them first?

On Tue, Sep 23, 2014 at 7:06 PM, William Le Ferrand <[email protected]>
wrote:

> Victor,
>
> It would be an unbounded stream of ordered items (potentially as slow as
> the slowest source stream)
>
> On Tue, Sep 23, 2014 at 3:59 PM, √iktor Ҡlang <[email protected]>
> wrote:
>
>> Hi William,
>>
>> I am not sure I understand the question, given N unbounded streams of
>> comparable items, what does the resulting stream look like?
>>
>> On Tue, Sep 23, 2014 at 1:31 PM, William Le Ferrand <[email protected]>
>> wrote:
>>
>>> Dear List,
>>>
>>> I've a set of reactive streams that contain ordered data. Is there an
>>> easy way to "sort merge" them into a single reactive stream? I couldn't
>>> find anything in the documentation nor on the web; I came up with a
>>> handmade solution but it looks unnecessary obfuscated
>>>
>>> Thanks in advance,
>>>
>>> Best
>>> William
>>>
>>> --
>>> William Le Ferrand
>>>
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>>
>>
>>
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>> Cheers,
>> √
>>
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>
>
>
> --
> William Le Ferrand
>
> Mobile : (+1) (415) 683-1484
> Web : http://williamleferrand.github.com/
> <http://www.linkedin.com/in/williamleferrand>
>
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-- 
Cheers,
√

-- 
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