Thanks a lot!
It's really helpful!
Leon
在 2015年9月1日星期二 UTC-7上午11:54:48，Lance Arlaus写道：
>
> Leon-
>
> There's a couple of ways to solve this, but one simple solution is to use
> a combination of Broadcast, filter, and Merge.
> 1. Broadcast the elements to two branches and filter each branch. Assuming
> the respective filters are mutually exclusive, each element will only go
> down a single branch.
> 2. Place the FlowB on the desired branch to receive extra processing.
> 3. Place the Merge prior to FlowC to join the two branches
>
> The result will look something like this:
> FlowA ~> bcast ~> nonfilter ~> FlowB ~> merge
> ~> filter ~> merge
> ~> merge.out
> ~> FlowC
>
> However, an even simpler solution, depending on your requirements, is to
> just implement FlowB as a map stage that passes through on false match.
> Something like:
>
> val flowB = Flow[T].map(e => cond(e) match {
> case true => // do something
> case false => e
> }
>
> You can then just chain via() calls (flowA.via(flowB).via(flowC)). A wee
> bit simpler if it fits your case.
>
> Lance
>
>
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