Hi John,


On Wed, Jan 13, 2016 at 4:26 PM, <[email protected]> wrote:

> Yes that makes sense and helps me better undnerstand the streams api.
> I am struggling right now though. here is my pseudo code
>
> Flow<Integer, Pair<Try<HttpResponse>, Integer>, BoxedUnit> flow = ....;
>
> final Flow<Integer, ByteString, BoxedUnit> byteStringFlow = 
> flow.flatMapConcat(pair -> {
>    Try<HttpResponse> responseTry = pair.first();
>    return responseTry.get().entity().getDataBytes();
> });
>
>
> I am trying to hold onto the Integer and resulting Bytesring on flow that I 
> connect to
> byteStringFlow.
>
> I am trying to use viaMat but I cannot find a way to add it to
> byteStringFlow....
>
> A materialized value is a *single* value for the whole materialization,
while in the code above you will have a stream of Integers. What you first
need to figure out is how you want to get these, since for one Integer
there might be multiple ByteStrings belonging.

-Endre



>
>
>
>
> Am Mittwoch, 13. Januar 2016 16:09:38 UTC+1 schrieb drewhk:
>>
>> Hi,
>>
>> How would that work? It is an empty (identity) Flow, therefore it cannot
>> cannot change the type of the input to another type since elements are
>> unchanged.
>>
>> You need to add at least one combinator to the flow to change the output
>> types.
>>
>> -Endre
>>
>> On Wed, Jan 13, 2016 at 4:05 PM, <[email protected]> wrote:
>>
>>> I know  how to create a simple flow:
>>>
>>> Flow<Integer, Integer, BoxedUnit> flowUniform = Flow.create();
>>>
>>> But how-to create a not uniform flow?
>>>
>>> Flow<Integer, Pair<Try<HttpResponse>, Integer>, BoxedUnit> flowNotUniform = 
>>> Flow.create(); // this doesn't work
>>>
>>> Many Greetings John?
>>>
>>>
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-- 
Akka Team
Typesafe - Reactive apps on the JVM
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Twitter: @akkateam

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