I am having a hard time understanding how to use futures specifically when
it comes to implementing functions within those futures.
So for example, if I wanted to implement factorial in a future using this
algorithm:
int factorial(int n) {
if (n == 0)
return 1;
else
return (n * factorial(n-1));
}
My current guess is:
Future<Integer> f = future(new function <Integer, Integer>() {
public Integer apply(Integer i) {
if (i == 0) {
return 1;
}
else {
return (i * apply(n-1));
}
}
}, system.dispatcher());
results = f.onSuccess(new PrintResult<Integer>(),
system.dispatcher());
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