I came up with this before realizing my Flow (at least currently) is not
1:1 :(
def kafka1to1Flow[In,Out](job: Flow[In, Out, _]):
Graph[FlowShape[CommittableMessage[_,In], (Out, CommittableMessage[_,In])],
NotUsed] = {
val result = GraphDSL.create() { implicit b =>
import GraphDSL.Implicits._
val toValue: FlowShape[CommittableMessage[_,In], In] =
b.add(Flow[CommittableMessage[_,In]].map(_.record.value))
val bcast: UniformFanOutShape[CommittableMessage[_,In],
CommittableMessage[_,In]] = b.add(Broadcast[CommittableMessage[_,In]](2))
val zip: FanInShape2[Out, CommittableMessage[_,In], (Out,
CommittableMessage[_,In])] = b.add(Zip[Out, CommittableMessage[_,In]]())
bcast.out(0) ~> toValue ~> job ~> zip.in0
bcast.out(1) ~> zip.in1
FlowShape(bcast.in, zip.out)
}
result
}
On Wed, Oct 26, 2016 at 2:08 PM, Richard Rodseth <[email protected]> wrote:
> Yes, thanks. I'll explore this.
>
> On Wed, Oct 26, 2016 at 2:04 PM, Roland Kuhn <[email protected]> wrote:
>
>> Yes, indeed: if it is strictly 1:1 and it retains the order of the
>> messages, then this works. Thanks for the sample!
>>
>> Regards,
>>
>> Roland
>>
>> > 26 okt. 2016 kl. 22:12 skrev Itamar Ravid <[email protected]>:
>> >
>> > Broadcast/Zip if your existing flow is 1:1. Here's a sample:
>> https://github.com/iravid/stream-processing-talk/blob/master
>> /GraphDSL.scala#L86
>> >
>> > --
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